40x^5y^4/-8x^4y^6=5x/y^2

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Solution for 40x^5y^4/-8x^4y^6=5x/y^2 equation: 


D( x )

y^2 = 0

y^2 = 0

y^2 = 0

y^2 = 0

x należy do R

x belongs to the empty set

x^4*((40*x^5*y^4)/(-8))*y^6 = (5*x)/(y^2)

x belongs to the empty set

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